The compound which contains all the four 1^o, | vedclass

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(B) The classification of carbon atoms depends on the number of other carbon atoms to which a specific carbon is bonded:   $1^o$ (Primary) Bonded to $

Vedclass · Accepted Answer

$3-$ chloro $-2, 3-$ dimethylpentane

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(B) The classification of carbon atoms depends on the number of other carbon atoms to which a specific carbon is bonded:   $1^o$ (Primary) Bonded to $1$ other carbon   $2^o$ (Secondary) Bonded to $2$ other carbons   $3^o$ (Tertiary) Bonded to $3$ other carbons   $4^o$ (Quaternary) Bonded to $4$ other carbons   Let us analyze $3-$ chloro $-2, 3-$ dimethylpentane: $CH_3-CH(CH_3)-C(Cl)(CH_3)-CH_2-CH_3$. - $1^o$ carbons: The terminal $CH_3$ groups. - $2^o$ carbon: The $-CH_2-$ group at position $4$. - $3^o$ carbon: The $-CH-$ group at position $2$. - $4^o$ carbon: The carbon at position $3$ is bonded to four other atoms (three carbons and one chlorine atom),satisfying the quaternary carbon definition.

The compound which contains all the four $1^o, 2^o, 3^o$ and $4^o$ carbon atoms is

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