The compound shown in the image is prepared i | vedclass

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(C) The compound shown is methyl tert-butyl ether,$(CH_3)_3C-O-CH_3$.Williamson ether synthesis is the best method for preparing unsymmetrical ethers.

Vedclass · Accepted Answer

$(CH_3)_3C-OK + CH_3-Br \rightarrow (CH_3)_3C-O-CH_3$

Vedclass · Answer

(C) The compound shown is methyl tert-butyl ether,$(CH_3)_3C-O-CH_3$.Williamson ether synthesis is the best method for preparing unsymmetrical ethers.It involves the reaction of an alkoxide ion with a primary alkyl halide.To obtain a high yield,the alkyl halide should be primary (to avoid elimination) and the alkoxide should be bulky if necessary.Reaction: $(CH_3)_3C-OK + CH_3-Br \rightarrow (CH_3)_3C-O-CH_3 + KBr$.Here,$(CH_3)_3C-OK$ is the nucleophile (tert-butoxide) and $CH_3-Br$ is the primary alkyl halide (methyl bromide),which undergoes $S_N2$ reaction to form the ether.

The compound shown in the image is prepared in high yield by the reaction:

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