The compound interest (in ₹) on ₹ 10000 at 20 | vedclass

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(B) Given: Principal $(P)$ = ₹ $10000$,Rate $(R)$ = $20 \%$ per annum,Time $(t)$ = $1$ year $6$ months = $1.5$ years.Since interest is calculated half

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$3310$

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(B) Given: Principal $(P)$ = ₹ $10000$,Rate $(R)$ = $20 \%$ per annum,Time $(t)$ = $1$ year $6$ months = $1.5$ years.Since interest is calculated half-yearly,the rate per half-year = $\frac{20}{2} = 10 \%$.The number of half-years $(n)$ = $1.5 	imes 2 = 3$.Using the compound interest formula: $CI = P \left[ \left( 1 + \frac{R}{100} ight)^n - 1 ight]$.$CI = 10000 \left[ \left( 1 + \frac{10}{100} ight)^3 - 1 ight]$.$CI = 10000 \left[ \left( \frac{11}{10} ight)^3 - 1 ight]$.$CI = 10000 \left[ \frac{1331}{1000} - 1 ight]$.$CI = 10000 \left[ \frac{331}{1000} ight]$.$CI = 10 	imes 331 = ₹ 3310$.

The compound interest (in ₹) on ₹ $10000$ at $20 \%$ per annum at the end of $1$ year $6$ months,if the interest is calculated half-yearly,will be:

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