The compound X (C_{7}H_{9}N) reacts with benz | vedclass

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(A) Benzene sulphonyl chloride,also known as Hinsberg's reagent,reacts with $1^{\circ}$ and $2^{\circ}$ amines to form sulphonamides.The sulphonamide

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(A) Benzene sulphonyl chloride,also known as Hinsberg's reagent,reacts with $1^{\circ}$ and $2^{\circ}$ amines to form sulphonamides.The sulphonamide formed from a $1^{\circ}$ amine contains an acidic hydrogen atom attached to the nitrogen,making it soluble in alkali.The sulphonamide formed from a $2^{\circ}$ amine does not contain any acidic hydrogen atom attached to the nitrogen,making it insoluble in alkali.Given that compound $X (C_{7}H_{9}N)$ reacts with benzene sulphonyl chloride to form a product $Y$ that is insoluble in alkali,$X$ must be a $2^{\circ}$ amine.Among the given options,$N$-methylaniline $(C_{6}H_{5}NHCH_{3})$ is a $2^{\circ}$ amine,which satisfies the given conditions.

The compound $X (C_{7}H_{9}N)$ reacts with benzene sulphonyl chloride to give $Y (C_{13}H_{13}NO_{2}S)$ which is insoluble in alkali. The compound $X$ is

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