The complex hexamineplatinum(IV) chloride wil | vedclass

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Question

(D) The chemical formula of hexamineplatinum$(IV)$ chloride is $[Pt(NH_3)_6]Cl_4$. Upon ionization in an aqueous solution,it dissociates as follows: $

Vedclass · Accepted Answer

$5$

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(D) The chemical formula of hexamineplatinum$(IV)$ chloride is $[Pt(NH_3)_6]Cl_4$. Upon ionization in an aqueous solution,it dissociates as follows: $[Pt(NH_3)_6]Cl_4 \rightarrow [Pt(NH_3)_6]^{4+} + 4Cl^-$. This results in one complex cation $[Pt(NH_3)_6]^{4+}$ and four chloride anions $4Cl^-$. Total number of ions = $1 + 4 = 5$ ions.

The complex hexamineplatinum$(IV)$ chloride will give how many ions upon ionization?

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