The coefficient of performance of a Carnot re | vedclass

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(C) The coefficient of performance $(K)$ of a Carnot refrigerator is given by the formula:$K = \frac{T_2}{T_1 - T_2}$Here,$T_2$ is the temperature of

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$9$

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(C) The coefficient of performance $(K)$ of a Carnot refrigerator is given by the formula:$K = \frac{T_2}{T_1 - T_2}$Here,$T_2$ is the temperature of the cold reservoir and $T_1$ is the temperature of the hot reservoir.Given:$T_2 = 0^oC = (0 + 273) K = 273 K$$T_1 = 30^oC = (30 + 273) K = 303 K$Substituting these values into the formula:$K = \frac{273}{303 - 273} = \frac{273}{30} = 9.1$Wait,recalculating: $273 / 30 = 9.1$. Given the options,$9$ is the closest integer value.

The coefficient of performance of a Carnot refrigerator working between $30^oC$ and $0^oC$ is

Similar Questions

The temperature of the freezer compartment of an ideal refrigerator is $-13 \, ^\circ C$. If the coefficient of performance of the refrigerator is $5$,then the temperature of the surroundings (to which heat is rejected) is:

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If the door of a refrigerator is kept open,then which of the following is true?

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