The coefficient of $x^2$ in the expansion of $(1-3x)^{-1/4}$ is

  • A
    $\frac{45}{64}$
  • B
    $\frac{45}{8}$
  • C
    $\frac{45}{16}$
  • D
    $\frac{45}{32}$

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Similar Questions

The cube root of $217$ is:

If $x=\frac{2}{5}+\frac{1 \cdot 3}{2 !}\left(\frac{2}{5}\right)^2+\frac{1 \cdot 3 \cdot 5}{3 !}\left(\frac{2}{5}\right)^3+\ldots$,then $x+\frac{1}{x}=$

The correct matching of List-$I$ from List-$II$ is:
List-$I$ List-$II$
$(A)$ $(1-x)^{-n}$ $(i)$ $\frac{x}{x+1}$
$(B)$ $(1+x)^{-n}$ $(ii)$ $1-nx+\frac{n(n+1)}{2!}x^2-\dots$ if $|x| < 1$
$(C)$ If $x>1$,then $1+\frac{1}{x}+\frac{1}{x^2}+\dots$ is $(iii)$ $1+nx+\frac{n(n+1)}{2!}x^2+\dots$ if $|x| < 1$
$(D)$ If $|x|>1$,then $1-\frac{2}{x^2}+\frac{3}{x^4}-\frac{4}{x^6}+\dots$ is $(iv)$ $\frac{x}{x-1}$
  $(v)$ $\frac{x^4}{(x^2+1)^2}$
  $(vi)$ $\frac{x^4}{(x^2-1)^2}$

The ${(r + 1)^{th}}$ term in the expansion of ${(1 - x)^{-4}}$ is:

The coefficient of $x^n$ in $\frac{(1 + x)^2}{(1 - x)^3}$ is

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