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(B) The object is located on the $y$-axis at a distance of $10 	ext{ cm}$ from the origin $c$. Its coordinates are $(0, 10)$.The mirror makes an angl

Vedclass · Accepted Answer

$\left( 5, -5\sqrt{3} \right)$

Vedclass · Answer

(B) The object is located on the $y$-axis at a distance of $10 	ext{ cm}$ from the origin $c$. Its coordinates are $(0, 10)$.The mirror makes an angle of $30^{\circ}$ with the negative $x$-axis,which means it makes an angle of $150^{\circ}$ with the positive $x$-axis.The angle of the normal to the mirror with the $y$-axis is $30^{\circ}$.The image of an object at distance $d$ from the mirror along a line making angle $	heta$ with the mirror surface will be at distance $d$ on the other side.Using the geometry of reflection,the image $I$ is at a distance of $10 	ext{ cm}$ from the origin $c$.The angle the line joining the origin to the image makes with the positive $x$-axis is $-60^{\circ}$ (or $300^{\circ}$).Thus,the coordinates of the image are $(10 \cos(-60^{\circ}), 10 \sin(-60^{\circ})) = (10 	imes 0.5, 10 	imes -\frac{\sqrt{3}}{2}) = (5, -5\sqrt{3})$.Therefore,the correct option is $B$.

The coordinates of the image with respect to the origin $c$ will be

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