(N/A) Taking $C$ as the origin $(0,0)$,$CB$ as the $x$-axis,and $CD$ as the $y$-axis:
$1$. The coordinates of the vertices are determined by counting the units from the origin $C$ along the axes.
$2$. The coordinates of the vertices $P, Q,$ and $R$ are $P(12, 2), Q(13, 6),$ and $R(10, 3)$.
$3$. The area of a triangle with vertices $(x_1, y_1), (x_2, y_2),$ and $(x_3, y_3)$ is given by:
$\text{Area} = \frac{1}{2} |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|$
$4$. Substituting the values:
$\text{Area} = \frac{1}{2} |12(6 - 3) + 13(3 - 2) + 10(2 - 6)|$
$\text{Area} = \frac{1}{2} |12(3) + 13(1) + 10(-4)|$
$\text{Area} = \frac{1}{2} |36 + 13 - 40|$
$\text{Area} = \frac{1}{2} |9| = 4.5 \text{ square units}$.