(B) In $XeO_3$,the $Xe$ atom is $sp^3$ hybridized with one lone pair,resulting in a pyramidal geometry.In $XeOF_4$,the $Xe$ atom is $sp^3d^2$ hybridiz

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(B) In $XeO_3$,the $Xe$ atom is $sp^3$ hybridized with one lone pair,resulting in a pyramidal geometry.In $XeOF_4$,the $Xe$ atom is $sp^3d^2$ hybridized with one lone pair,resulting in a square pyramidal geometry.

Class 12 Chemistry p-Block Elements (Class 12)Noble gases

Medium

The chemical structures of $XeO_3$ and $XeOF_4$,respectively,are

TS EAMCET 2022 All TS EAMCET

A
Planar; Trigonal bipyramidal
B
Pyramidal; Square pyramidal
C
Planar; Square pyramidal
D
Pyramidal; Square planar

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p-Block Elements (Class 12)

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Noble gases

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Complete hydrolysis of $XeF_4$ and $XeF_6$ gives its oxides $P$ and $Q$,respectively. Identify $P$ and $Q$.

MediumTS EAMCET 2021

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Why has it been difficult to study the chemistry of radon?

Medium

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What is the atomic number $(Z)$ of the noble gas that reacts with fluorine?

Easy

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Match the compounds of $Xe$ in Column-$I$ with the molecular structure in Column-$II$.

Column-$I$ Column-$II$

$(a)$ $XeF_2$ $(i)$ Square planar

$(b)$ $XeF_4$ $(ii)$ Linear

$(c)$ $XeO_3$ $(iii)$ Square pyramidal

$(d)$ $XeOF_4$ $(iv)$ Pyramidal

Column-$I$	Column-$II$
$(a)$ $XeF_2$	$(i)$ Square planar
$(b)$ $XeF_4$	$(ii)$ Linear
$(c)$ $XeO_3$	$(iii)$ Square pyramidal
$(d)$ $XeOF_4$	$(iv)$ Pyramidal

MediumNEET 2020

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The hybridisation of $Xe$ in $XeO_3$ is

MediumTS EAMCET 2020

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The chemical structures of $XeO_3$ and $XeOF_4$,respectively,are

Similar Questions

Complete hydrolysis of $XeF_4$ and $XeF_6$ gives its oxides $P$ and $Q$,respectively. Identify $P$ and $Q$.

Why has it been difficult to study the chemistry of radon?

What is the atomic number $(Z)$ of the noble gas that reacts with fluorine?

Match the compounds of $Xe$ in Column-$I$ with the molecular structure in Column-$II$. Column-$I$ Column-$II$ $(a)$ $XeF_2$ $(i)$ Square planar $(b)$ $XeF_4$ $(ii)$ Linear $(c)$ $XeO_3$ $(iii)$ Square pyramidal $(d)$ $XeOF_4$ $(iv)$ Pyramidal

The hybridisation of $Xe$ in $XeO_3$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Match the compounds of $Xe$ in Column-$I$ with the molecular structure in Column-$II$.

Column-$I$ Column-$II$

$(a)$ $XeF_2$ $(i)$ Square planar

$(b)$ $XeF_4$ $(ii)$ Linear

$(c)$ $XeO_3$ $(iii)$ Square pyramidal

$(d)$ $XeOF_4$ $(iv)$ Pyramidal