(C) Let the oxidation state of $Co$ be $x$. The charge on the cyanide ligand $(CN^-)$ is $-1$. The overall charge on the complex $[Co(CN)_6]^{3-}$ is

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(C) Let the oxidation state of $Co$ be $x$. The charge on the cyanide ligand $(CN^-)$ is $-1$. The overall charge on the complex $[Co(CN)_6]^{3-}$ is $-3$. Therefore,the equation is: $x + 6(-1) = -3$. $x - 6 = -3$. $x = +3$. Thus,the oxidation state of $Co$ is $+3$.