The charge on the capacitor of capacitance 15 | vedclass

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(A) The capacitors with capacitances $C_1 = 10 \; \mu F$,$C_2 = 15 \; \mu F$,and $C_3 = 20 \; \mu F$ are connected in series with a voltage source of

Vedclass · Accepted Answer

$60$

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(A) The capacitors with capacitances $C_1 = 10 \; \mu F$,$C_2 = 15 \; \mu F$,and $C_3 = 20 \; \mu F$ are connected in series with a voltage source of $V = 13 \; V$.The equivalent capacitance $C_{eq}$ for capacitors in series is given by:$\frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3}$Substituting the values:$\frac{1}{C_{eq}} = \frac{1}{10} + \frac{1}{15} + \frac{1}{20} = \frac{6 + 4 + 3}{60} = \frac{13}{60} \; \mu F^{-1}$Therefore,$C_{eq} = \frac{60}{13} \; \mu F$.The total charge $Q$ supplied by the source is:$Q = C_{eq} 	imes V = \left( \frac{60}{13} \; \mu F ight) 	imes 13 \; V = 60 \; \mu C$.Since the capacitors are connected in series,the charge on each capacitor is the same and equal to the total charge $Q$.Thus,the charge on the $15 \; \mu F$ capacitor is $60 \; \mu C$.

The charge on the capacitor of capacitance $15 \; \mu F$ in the figure given below is $\dots \; \mu C$.

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