The chance of India winning the toss is $3/4$. If it wins the toss,then its chance of victory is $4/5$,otherwise it is only $1/2$. Then the chance of India's victory is:

Events $A$ and $B$ are independent events and $P(A)=P$,$P(B)=\frac{1}{2}$ and $P(A \cup B)=\frac{3}{5}$,then the value of $P$ is . . . . . . .

$A$ bag $X$ contains $2$ white and $3$ black balls,and another bag $Y$ contains $4$ white and $2$ black balls. If one bag is selected at random and one ball is drawn from it,what is the probability that the ball is white?

$A$ purse contains $4$ copper coins and $3$ silver coins,the second purse contains $6$ copper coins and $2$ silver coins. If a coin is drawn out of one of these purses,then the probability that it is a copper coin is :-

Urn $A$ contains $6$ white and $2$ black balls; urn $B$ contains $5$ white and $3$ black balls and urn $C$ contains $4$ white and $4$ black balls. If an urn is chosen at random and a ball is drawn at random from it,then the probability that the ball drawn is white is

$A$ and $B$ are two independent events such that $P(A) = \frac{1}{2}$ and $P(B) = \frac{1}{3}$. Then $P$ (neither $A$ nor $B$) is equal to