The cell reaction $Mn + 2Ag_{(C_1)}^{+(aq)} \to Mn_{(C_2)}^{+2_{(aq)}} + 2Ag$ is represented by

Arrange the following metals in the order in which they displace each other from the solution of their salts: $Al$,$Cu$,$Fe$,$Mg$,and $Zn$.

Standard electrode potentials of $Zn$ and $Fe$ are known to be $(i) -0.76 \ V$ and $(ii) -0.44 \ V$ respectively. How does this explain that galvanization prevents rusting of iron while zinc slowly dissolves away?

The standard electrode potential of $Zn^{2+}/Zn$ is $-0.76\, V$ and that of $Cu^{2+}/Cu$ is $0.34\, V$. The emf $(V)$ and the free energy change $(kJ\, mol^{-1})$,respectively for a Daniell cell will be

Assertion : If $\lambda^o_{Na^{+}}$ and $\lambda^o_{Cl^{-}}$ are molar limiting conductivity of sodium and chloride ions respectively,then the limiting molar conductivity for sodium chloride is given by the equation :
$\Lambda^o_{NaCl} = \lambda^o_{Na^{+}} + \lambda^o_{Cl^{-}}$
Reason : This is according to Kohlrausch law of independent migration of ions.

Standard free energies of formation (in $kJ/mol$) at $298 \ K$ are $-237.2$,$-394.4$,and $-8.2$ for $H_2O_{(l)}$,$CO_{2_{(g)}}$,and pentane$_{(g)}$ respectively. The value of $E^o_{cell}$ for the pentane-oxygen fuel cell is .......... $V$.