The Cartesian coordinates of the point whose | vedclass

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(D) Given polar coordinates are $P(r, 	heta) = \left(\frac{1}{2}, 120^{\circ}ight)$,where $r = \frac{1}{2}$ and $	heta = 120^{\circ}$.We use the c

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$\left(\frac{-1}{4}, \frac{\sqrt{3}}{4}\right)$

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(D) Given polar coordinates are $P(r, 	heta) = \left(\frac{1}{2}, 120^{\circ}ight)$,where $r = \frac{1}{2}$ and $	heta = 120^{\circ}$.We use the conversion formulas $x = r \cos 	heta$ and $y = r \sin 	heta$.For $x$: $x = \frac{1}{2} \cos 120^{\circ} = \frac{1}{2} \left(-\frac{1}{2}ight) = -\frac{1}{4}$.For $y$: $y = \frac{1}{2} \sin 120^{\circ} = \frac{1}{2} \left(\frac{\sqrt{3}}{2}ight) = \frac{\sqrt{3}}{4}$.Therefore,the Cartesian coordinates are $\left(-\frac{1}{4}, \frac{\sqrt{3}}{4}ight)$.

The Cartesian coordinates of the point whose polar coordinates are $\left(\frac{1}{2}, 120^{\circ}\right)$ are:

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