The bulk modulus of a liquid is $3 \times 10^{10} \ Nm^{-2}$. The pressure required to reduce the volume of liquid by $2 \%$ is ........ $\times 10^{8} \ Nm^{-2}$.

  • A
    $3$
  • B
    $9$
  • C
    $6$
  • D
    $12$

Explore More

Similar Questions

If the Bulk modulus of lead is $8.0 \times 10^9 \, N/m^2$ and the initial density of the lead is $11.4 \, g/cc$,then under the pressure of $2.0 \times 10^8 \, N/m^2$,the density of the lead is ............. $g/cc$.

Difficult
View Solution

The normal density of a material is $\rho$ and its bulk modulus of elasticity is $K$. The magnitude of increase in density of the material,when a pressure $P$ is applied uniformly on all sides,will be

The compressibility of a material is defined as:

When a pressure of $100 \, atm$ is applied to a rubber ball,its volume decreases by $0.01 \%$. What is the bulk modulus of the rubber?

The increase in the pressure required to decrease the volume $(\Delta V)$ of water is $6.3 \times 10^7 \text{ N/m}^2$. The percentage decrease in the volume is . . . . . . . (Bulk modulus of water = $2.1 \times 10^9 \text{ N/m}^2$.) (in $\%$)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo