The Boolean expression of the circuit given in the figure is

  • A
    $Y=A+\bar{B}$
  • B
    $Y=\overline{A+B}$
  • C
    $Y=\bar{A}+B$
  • D
    $Y=A+B$

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In the given circuit,if $A=0, B=1$ and $C=1$ are inputs,then the values of $y_1$ and $y_2$ are respectively

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