The bond order of which of the following two | vedclass

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(B) The bond order of $C_2$ and $O_2$ is the same.For $C_2$ ($12$ electrons),the molecular orbital configuration is $\sigma 1s^2, \sigma^* 1s^2, \sigm

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$C_2, O_2$

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(B) The bond order of $C_2$ and $O_2$ is the same.For $C_2$ ($12$ electrons),the molecular orbital configuration is $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2p_x^2 = \pi 2p_y^2$.Bond order = $\frac{1}{2}(N_b - N_a) = \frac{1}{2}(8 - 4) = 2$.For $O_2$ ($16$ electrons),the molecular orbital configuration is $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^1 = \pi^* 2p_y^1$.Bond order = $\frac{1}{2}(10 - 6) = 2$.

Pair of species	Identical property
$A$. $B_2 \& O_2$	$P$. Bond order $= 2.5$
$B$. $Be_2 \& H_2^{2-}$	$Q$. Paramagnetic nature
$C$. $N_2^{+} \& N_2^{-}$	$R$. Diamagnetic nature
$D$. $O_2^{+} \& O_2^{-}$	$S$. Doesn't exist

The bond order of which of the following two species is the same?

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Pair of species Identical property

$A$. $B_2 \& O_2$ $P$. Bond order $= 2.5$

$B$. $Be_2 \& H_2^{2-}$ $Q$. Paramagnetic nature

$C$. $N_2^{+} \& N_2^{-}$ $R$. Diamagnetic nature

$D$. $O_2^{+} \& O_2^{-}$ $S$. Doesn't exist

Which of the following species are paramagnetic: $O_2, O_2^-, O_2^{2-}$?

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