The bond dissociation energy is highest for

  • A
    $Cl_2$
  • B
    $I_2$
  • C
    $Br_2$
  • D
    $F_2$

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Compound $A$ and $B$ respectively are :-
$Cl_2 + 2NaOH (cold \& dil.) \rightarrow A + NaCl + H_2O$
$3Cl_2 + 6NaOH (hot \& conc.) \rightarrow B + 5NaCl + 3H_2O$

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