The bond angle in NF_{3} (102.3^{circ}) is sm | vedclass

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(C) In $NH_{3}$,the electronegativity of $N$ $(3.04)$ is higher than that of $H$ $(2.20)$,so the bonding electron pairs are shifted towards $N$. This

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opposite polarity of $N$ in the two molecules

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(C) In $NH_{3}$,the electronegativity of $N$ $(3.04)$ is higher than that of $H$ $(2.20)$,so the bonding electron pairs are shifted towards $N$. This increases the repulsion between the bonding pairs,leading to a larger bond angle $(107.2^{\circ})$.In $NF_{3}$,the electronegativity of $F$ $(3.98)$ is higher than that of $N$ $(3.04)$,so the bonding electron pairs are shifted away from $N$ towards $F$. This reduces the repulsion between the bonding pairs,resulting in a smaller bond angle $(102.3^{\circ})$.Therefore,the difference in the polarity of the $N-X$ bond (where $X = H$ or $F$) causes the difference in bond angles.

The bond angle in $NF_{3}$ $(102.3^{\circ})$ is smaller than $NH_{3}$ $(107.2^{\circ})$. This is because of

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