The binding energy of deuteron is 2.2,MeV and | vedclass

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(B) The nuclear fusion reaction is given by: $2(_1^2H) \rightarrow _2^4He + Q$.The energy released $(Q)$ in a nuclear reaction is equal to the differe

Vedclass · Accepted Answer

$23.6$

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(B) The nuclear fusion reaction is given by: $2(_1^2H) ightarrow _2^4He + Q$.The energy released $(Q)$ in a nuclear reaction is equal to the difference between the total binding energy of the products and the total binding energy of the reactants.Total binding energy of the reactants (two deuterons) $= 2 	imes 2.2\,MeV = 4.4\,MeV$.Total binding energy of the product ($^4He$ nucleus) $= 28\,MeV$.Energy released $(Q)$ $= (	ext{Binding energy of product}) - (	ext{Binding energy of reactants})$.$Q = 28\,MeV - 4.4\,MeV = 23.6\,MeV$.

The binding energy of deuteron is $2.2\,MeV$ and that of $_2^4He$ is $28\,MeV$. If two deuterons are fused to form one $_2^4He$ nucleus, then the energy released is ......... $MeV$.

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