The binding energy $(BE)$ per nucleon for an element is $7.14 \text{ MeV}$. If the total $BE$ of the element is $28.6 \text{ MeV}$,then the number of nucleons in the element is:
- A$4$
- B$8$
- C$16$
- D$32$
Explore More
Similar Questions
The mass equivalent of $931\, MeV$ energy is
Easy
View SolutionThe binding energy per nucleon for $C^{12}$ is $7.68 \text{ MeV}$ and that for $C^{13}$ is $7.5 \text{ MeV}$. The energy required to remove a neutron from $C^{13}$ is ......... $\text{MeV}$.
Medium
View SolutionWhat is the energy equivalent to one kilogram of mass?
Medium
View SolutionThe energy equivalent of $0.5\, g$ of a substance is $........\, J$.
Write the equation of mass-energy equivalence.
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo