The basicity of aniline is weaker in comparis | vedclass

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(B) In aniline $(C_6H_5NH_2)$,the lone pair of electrons on the nitrogen atom is delocalized into the benzene ring through resonance. This reduces the

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resonance effect of the phenyl group in aniline

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(B) In aniline $(C_6H_5NH_2)$,the lone pair of electrons on the nitrogen atom is delocalized into the benzene ring through resonance. This reduces the availability of the lone pair for protonation,making aniline a weaker base. In contrast,in methylamine $(CH_3NH_2)$,the electron-donating methyl group increases the electron density on the nitrogen atom,making it more basic than aniline.

The basicity of aniline is weaker in comparison to that of methylamine due to

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The product obtained by the electrolytic reduction of nitrobenzene in the presence of $H_2SO_4$ is:

Assertion : Amines are basic in nature.
Reason : Presence of a lone pair of electrons on the nitrogen atom.

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Assertion : Aniline does not undergo Friedel-Crafts reaction.
Reason : $-NH_2$ group of aniline reacts with $AlCl_3$ (Lewis acid) to give acid-base reaction.

Which of the following reaction/s will not give $p-$aminoazobenzene?

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