The average value of the potential difference | vedclass

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(C) The average value of a periodic function is given by the area under the curve over one complete time period divided by the time period.From the fi

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$\frac{V_0}{4}$

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(C) The average value of a periodic function is given by the area under the curve over one complete time period divided by the time period.From the figure,the potential difference $V$ is non-zero only from $t = 0$ to $t = T/2$ within one cycle of duration $T$.The area under the $V-t$ graph for one cycle is the area of the triangle with base $T/2$ and height $V_0$:$	ext{Area} = \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height} = \frac{1}{2} 	imes \frac{T}{2} 	imes V_0 = \frac{V_0 T}{4}$.The average value $\langle V angle$ is:$\langle V angle = \frac{	ext{Area}}{T} = \frac{\frac{V_0 T}{4}}{T} = \frac{V_0}{4}$.

The average value of the potential difference $V$ shown in the figure is:

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