The average of consecutive numbers is n . If | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

Let, the numbers be $n-1, n$ and $n+1$. Their average

$=n$

The next two consecutive numbers are $n+2$ and $n+3$.

Therefore, the average of th

Vedclass · Accepted Answer

increase by $1$

Vedclass · Answer

Let, the numbers be $n-1, n$ and $n+1$. Their average

$=n$

The next two consecutive numbers are $n+2$ and $n+3$.

Therefore, the average of the five numbers

$=\frac{(n-1)+n+(n+1)+(n+2)+(n+3)}{5}$

$=\frac{5 n+5}{5}$

$=n+1$

The average of consecutive numbers is $n .$ If the next two consecutive numbers are also included, the average of the five numbers will

Similar Questions

The sum of five consecutive integers is $a$ and the sum of next five consecutive integers is $b$. Then $\frac{(b-a)}{100}$ is equal to

The average of five consecutive positive integers is $n$. If the next two integers are also included, the average of all these integers will

The average of first nine prime numbers is

The mean of the marks obtained by $100$ students is $60 .$ If the marks obtained by one of the students was incorrectly calculated as $75$ whereas the actual marks obtained by him were $65,$ what is the correct mean of the marks obtained by the students?