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Question

Let the $5$ consecutive integers be $m , m +1, m +2, m +3, m +4$

$m+m+1+m+2+m+3+m+4=5 n$

$5 m+10=5 n \Rightarrow n=m+2$

Now, the average of $

Vedclass · Accepted Answer

$\frac{2 n+5}{2}$

Vedclass · Answer

Let the $5$ consecutive integers be $m , m +1, m +2, m +3, m +4$

$m+m+1+m+2+m+3+m+4=5 n$

$5 m+10=5 n \Rightarrow n=m+2$

Now, the average of $6$ consective number starting with $( m +2)$

$=\frac{[m +2+ m +3+ m +4+m+5+m+6+m+7]}{6}=\frac{6 m+27}{6}$

$=\frac{2 m+9}{2}=\frac{2(n-2)+9}{2}=\frac{2 n+5}{2}$

The average of $5$ consecutive integers starting with $m$ is $n$. What is the average of $6$ consecutive integers starting with $( m +2) ?$

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