The average molar mass of chlorine is 35.5 g | vedclass

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(D) Let the mole ratio of $^{35}Cl$ to $^{37}Cl$ be $x:1$.The average molar mass is given by the formula: $	ext{Average molar mass} = \frac{n_{1} M_{

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$3$

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(D) Let the mole ratio of $^{35}Cl$ to $^{37}Cl$ be $x:1$.The average molar mass is given by the formula: $	ext{Average molar mass} = \frac{n_{1} M_{1} + n_{2} M_{2}}{n_{1} + n_{2}}$Substituting the given values: $35.5 = \frac{x 	imes 35 + 1 	imes 37}{x + 1}$$35.5(x + 1) = 35x + 37$$35.5x + 35.5 = 35x + 37$$35.5x - 35x = 37 - 35.5$$0.5x = 1.5$$x = \frac{1.5}{0.5} = 3$Therefore,the ratio of $^{35}Cl$ to $^{37}Cl$ is $3:1$.

Isotope	Natural abundance (%)	Molar mass $(u)$
$^{35}Cl$	$75.77$	$34.9689$
$^{37}Cl$	$24.23$	$36.9659$

The average molar mass of chlorine is $35.5 \ g \ mol^{-1}$. The ratio of $^{35}Cl$ to $^{37}Cl$ in naturally occurring chlorine is close to : (in $:1$)

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Calculate the average atomic mass of chlorine using the following data:

Isotope Natural abundance (%) Molar mass $(u)$

$^{35}Cl$ $75.77$ $34.9689$

$^{37}Cl$ $24.23$ $36.9659$
(in $u$)

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