The average force applied on the walls of a c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The pressure $P$ exerted by an ideal gas on the walls of a container is given by the kinetic theory of gases as $P = \frac{1}{3} \rho v_{rms}^{2}$

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(A) The pressure $P$ exerted by an ideal gas on the walls of a container is given by the kinetic theory of gases as $P = \frac{1}{3} ho v_{rms}^{2}$.From the ideal gas equation,$PV = nRT$,we have $P = \frac{nRT}{V}$.Since $n$,$R$,and $V$ are constant for a closed container,the pressure $P$ is directly proportional to the temperature $T$,i.e.,$P \propto T$.The force $F$ exerted on the walls is given by $F = P 	imes A$,where $A$ is the surface area of the wall.Since $A$ is constant for a closed container,$F \propto P$.Therefore,$F \propto T$,which implies $F \propto T^{1}$.Comparing this with $T^{x}$,we get $x = 1$.

The average force applied on the walls of a closed container depends as $T^{x}$ where $T$ is the temperature of an ideal gas. The value of $x$ is

Similar Questions

The temperature of a gas is $-78^{\circ} C$ and the average translational kinetic energy of its molecules is $K$. The temperature at which the average translational kinetic energy of the molecules of the same gas becomes $2K$ is: (in $^{\circ} C$)

If $r.m.s.$ velocity of a gas is $V_{rms} = 1840 \ m/s$ and its density $\rho = 8.99 \times 10^{-2} \ kg/m^3$,the pressure of the gas will be

The energy of all molecules of a monoatomic gas having a volume $V$ and pressure $P$ is $\frac{3}{2}PV$. The total translational kinetic energy of all molecules of a diatomic gas at the same volume and pressure is:

What is the pressure of hydrogen in a cylinder of volume $10 \text{ litre}$ if its total energy of translation is $7.5 \times 10^3 \text{ J}$?

$A$ flask contains Hydrogen and Argon in the ratio $2:1$ by mass. The temperature of the mixture is $30^{\circ} C$. The ratio of average kinetic energy per molecule of the two gases $(K_{\text{argon}} / K_{\text{hydrogen}})$ is: (Given: Atomic weight of $Ar = 39.9$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module