The atomic weight of an element is 39. The nu | vedclass

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(A) Let the number of protons be $Z$. Since the atom is neutral,the number of electrons is also $Z$.Given that the number of neutrons $(N)$ is one mor

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$19, 20, 19$

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(A) Let the number of protons be $Z$. Since the atom is neutral,the number of electrons is also $Z$.Given that the number of neutrons $(N)$ is one more than the number of protons,we have $N = Z + 1$.The mass number $(A)$ is the sum of protons and neutrons: $A = Z + N$.Substituting the values,we get $39 = Z + (Z + 1)$.$39 = 2Z + 1$,which simplifies to $2Z = 38$,so $Z = 19$.Thus,the number of protons is $19$,the number of electrons is $19$,and the number of neutrons is $19 + 1 = 20$.The sequence of protons,neutrons,and electrons is $19, 20, 19$.

The atomic weight of an element is $39$. The number of neutrons in its nucleus is one more than the number of protons. The number of protons,neutrons,and electrons respectively in its atom would be

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