(A) The $IUPAC$ nomenclature for elements with atomic number $Z > 100$ uses specific roots for each digit: $0 = \text{nil}$,$1 = \text{un}$,$2 = \text

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(A) The $IUPAC$ nomenclature for elements with atomic number $Z > 100$ uses specific roots for each digit: $0 = \text{nil}$,$1 = \text{un}$,$2 = \text{bi}$,$3 = \text{tri}$,$4 = \text{quad}$,$5 = \text{pent}$,$6 = \text{hex}$,$7 = \text{sept}$,$8 = \text{oct}$,$9 = \text{enn}$.For Unnilunium: $\text{Un} (1) + \text{nil} (0) + \text{un} (1) + \text{ium} = 101$.Therefore,the atomic number of Unnilunium is $101$.

Class 11 Chemistry Classification of Elements and Periodicity in Properties Extended or long form of periodic table

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The atomic number of Unnilunium is $...........$

JEE MAIN 2020 All JEE MAIN

A
$101$
B
$95$
C
$98$
D
$106$

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Class 11

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Classification of Elements and Periodicity in Properties

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Extended or long form of periodic table

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Prove that according to quantum numbers,the $6^{th}$ period contains $32$ elements.

Medium

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Match the elements in List-$I$ with their symbols in List-$II$.

List-$I$ List-$II$

$(1)$ $Unnilbium$ $(A)$ $Db$

$(2)$ $Unnilennium$ $(B)$ $Lr$

$(3)$ $Unnilpentium$ $(C)$ $Mt$

$(4)$ $Unniltrium$ $(D)$ $Bh$

$(E)$ $No$

$(F)$ $Rg$

Easy

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The $IUPAC$ symbols for the element with atomic number $119$ would be:

MediumJEE MAIN 2019

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The Modern Periodic Table is based on the atomic number. Explain this with a table.

Medium

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The long form of the periodic table is based on:

Easy

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List-$I$	List-$II$
$(1)$ $Unnilbium$	$(A)$ $Db$
$(2)$ $Unnilennium$	$(B)$ $Lr$
$(3)$ $Unnilpentium$	$(C)$ $Mt$
$(4)$ $Unniltrium$	$(D)$ $Bh$
	$(E)$ $No$
	$(F)$ $Rg$

The atomic number of Unnilunium is $...........$

Similar Questions

Prove that according to quantum numbers,the $6^{th}$ period contains $32$ elements.

Match the elements in List-$I$ with their symbols in List-$II$. List-$I$ List-$II$ $(1)$ $Unnilbium$ $(A)$ $Db$ $(2)$ $Unnilennium$ $(B)$ $Lr$ $(3)$ $Unnilpentium$ $(C)$ $Mt$ $(4)$ $Unniltrium$ $(D)$ $Bh$ $(E)$ $No$ $(F)$ $Rg$

The $IUPAC$ symbols for the element with atomic number $119$ would be:

The Modern Periodic Table is based on the atomic number. Explain this with a table.

The long form of the periodic table is based on:

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Match the elements in List-$I$ with their symbols in List-$II$.

List-$I$ List-$II$

$(1)$ $Unnilbium$ $(A)$ $Db$

$(2)$ $Unnilennium$ $(B)$ $Lr$

$(3)$ $Unnilpentium$ $(C)$ $Mt$

$(4)$ $Unniltrium$ $(D)$ $Bh$

$(E)$ $No$

$(F)$ $Rg$