(C) The electronic configuration of an element with atomic number $Z = 35$ is: $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^5$ The $p-$ orbitals present

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(C) The electronic configuration of an element with atomic number $Z = 35$ is: $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^5$ The $p-$ orbitals present are $2p$,$3p$,and $4p$. The number of electrons in these orbitals are: $2p^6 = 6$ electrons $3p^6 = 6$ electrons $4p^5 = 5$ electrons Total number of electrons in all $p-$ orbitals $= 6 + 6 + 5 = 17$.