The area of the region bounded by the curve $y = |x - 5|$,$y = 0$,$x = 0$,and $x = 2$ is . . . . . . sq. units.

The area of the region lying in the first quadrant bounded by $y=4x^2$,$x=0$,$y=2$,and $y=4$ is

Find the area of the parabola $y^{2}=4ax$ bounded by its latus rectum.

$A$ curve satisfying the initial condition $y(1)= 0$ satisfies the differential equation $x \frac{dy}{dx}= y -x^2$. The area bounded by the curve and the $x$-axis is:

The area bounded by the parabola $y=x^2$ and the line $y=x$ is

The area of the region bounded by $y=||x-3|-4|-5$ and the $X$-axis is