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(D) The area of an equilateral triangle with side $a$ is given by the formula: $Area = \frac{\sqrt{3}}{4} a^2$.For a triangle with side $a_1 = 16\,cm$

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Four times

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(D) The area of an equilateral triangle with side $a$ is given by the formula: $Area = \frac{\sqrt{3}}{4} a^2$.For a triangle with side $a_1 = 16\,cm$,the area $A_1 = \frac{\sqrt{3}}{4} (16)^2 = \frac{\sqrt{3}}{4} 	imes 256$.For a triangle with side $a_2 = 8\,cm$,the area $A_2 = \frac{\sqrt{3}}{4} (8)^2 = \frac{\sqrt{3}}{4} 	imes 64$.To find how many times $A_1$ is of $A_2$,we calculate the ratio: $\frac{A_1}{A_2} = \frac{\frac{\sqrt{3}}{4} 	imes 256}{\frac{\sqrt{3}}{4} 	imes 64} = \frac{256}{64} = 4$.Therefore,the area of the triangle with side $16\,cm$ is $4$ times the area of the triangle with side $8\,cm$.

The area of an equilateral triangle with each side measuring $16\,cm$ is how many times the area of an equilateral triangle with each side measuring $8\,cm$?

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