The area of a field in the shape of a trapezi | vedclass

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(C) The area of a trapezium is given by the formula: $	ext{Area} = \frac{1}{2} 	imes (	ext{sum of parallel sides}) 	imes (	ext{height})$.Let the

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$75$

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(C) The area of a trapezium is given by the formula: $	ext{Area} = \frac{1}{2} 	imes (	ext{sum of parallel sides}) 	imes (	ext{height})$.Let the parallel sides be $5x$ and $3x$.The height (perpendicular distance) is $24 \, m$.Substituting the values into the formula:$1440 = \frac{1}{2} 	imes (5x + 3x) 	imes 24$$1440 = \frac{1}{2} 	imes (8x) 	imes 24$$1440 = 4x 	imes 24$$1440 = 96x$$x = \frac{1440}{96} = 15$.The larger parallel side is $5x = 5 	imes 15 = 75 \, m$.

The area of a field in the shape of a trapezium is $1440 \, m^2$. The perpendicular distance between its parallel sides is $24 \, m$. If the ratio of the parallel sides is $5:3$, the length of the larger parallel side is ....... $m$.

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