The approximate value of sqrt[3]{28} is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let $f(x) = x^{1/3}$. We need to find the value of $f(28)$.Let $x = 27$ and $\Delta x = 1$,so that $x + \Delta x = 28$.We know that $f(x) = x^{1/3

Vedclass · Accepted Answer

$3.037$

Vedclass · Answer

(B) Let $f(x) = x^{1/3}$. We need to find the value of $f(28)$.Let $x = 27$ and $\Delta x = 1$,so that $x + \Delta x = 28$.We know that $f(x) = x^{1/3}$,so $f'(x) = \frac{1}{3}x^{-2/3} = \frac{1}{3x^{2/3}}$.The formula for approximation is $f(x + \Delta x) \approx f(x) + f'(x) \Delta x$.Here,$f(27) = (27)^{1/3} = 3$.$f'(27) = \frac{1}{3(27)^{2/3}} = \frac{1}{3(9)} = \frac{1}{27}$.Therefore,$f(28) \approx 3 + \frac{1}{27} 	imes 1$.$f(28) \approx 3 + 0.037037... \approx 3.037$.

The approximate value of $\sqrt[3]{28}$ is

Similar Questions

The approximate value of $\log _{10} 99$ is (Given $\log _{10} e = 0.4343$)

If the area of a square is $575$ square units,then the approximate value of its side is

If the radius of a sphere is measured as $7 \text{ m}$ with an error of $0.02 \text{ m}$, then the approximate error in calculating its volume is (in $\pi \text{ m}^3$)

Using differentials,find the approximate value of $\sqrt{0.082}$. Let $f(x) = \sqrt{x}$.

The approximate value of $3^{2.001}$,given that $\log 3 = 1.0986$,is

Vedclass Test Series

Exam Paper Generator

Online Exam Module