The angle of elevation of the top of a tower at a point $G$ on the ground is $30^{\circ}$. On walking $20 \ m$ towards the tower,the angle of elevation becomes $60^{\circ}$. The height of the tower is equal to

  • A
    $\frac{10}{\sqrt{3}} \ m$
  • B
    $20 \sqrt{3} \ m$
  • C
    $\frac{20}{\sqrt{3}} \ m$
  • D
    $10 \sqrt{3} \ m$

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