The amplitude of 15 sin (1000 pi t) is modula | vedclass

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(B) The carrier wave is given by $V_c(t) = 15 \sin(1000 \pi t)$.Comparing this with $V_c(t) = A_c \sin(2 \pi f_c t)$,we get $2 \pi f_c = 1000 \pi$,so

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$A, D$ and $E$ only

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(B) The carrier wave is given by $V_c(t) = 15 \sin(1000 \pi t)$.Comparing this with $V_c(t) = A_c \sin(2 \pi f_c t)$,we get $2 \pi f_c = 1000 \pi$,so $f_c = 500 	ext{ Hz}$.The modulating signal is given by $V_m(t) = 10 \sin(4 \pi t)$.Comparing this with $V_m(t) = A_m \sin(2 \pi f_m t)$,we get $2 \pi f_m = 4 \pi$,so $f_m = 2 	ext{ Hz}$.An amplitude modulated signal consists of the carrier frequency $f_c$ and two sideband frequencies $(f_c - f_m)$ and $(f_c + f_m)$.Sideband frequencies are:Lower sideband: $f_c - f_m = 500 - 2 = 498 	ext{ Hz}$.Upper sideband: $f_c + f_m = 500 + 2 = 502 	ext{ Hz}$.Thus,the frequencies present are $500 	ext{ Hz}$,$498 	ext{ Hz}$,and $502 	ext{ Hz}$,which correspond to options $A, D,$ and $E$.

Column $A$	Column $B$
$A$. $D$-layer	$I$. $250-400 \ km$
$B$. $E$-layer	$II$. $170-190 \ km$
$C$. $F_1$-layer	$III$. $95-120 \ km$
$D$. $F_2$-layer	$IV$. $65-75 \ km$

The amplitude of $15 \sin (1000 \pi t)$ is modulated by $10 \sin (4 \pi t)$ signal. The amplitude modulated signal contains frequency(ies) of
$A) 500 \text{ Hz}$
$B) 2 \text{ Hz}$
$C) 250 \text{ Hz}$
$D) 498 \text{ Hz}$
$E) 502 \text{ Hz}$
Choose the correct answer from the options given below:

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Choose the correct statement for amplitude modulation.

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The amplitude of $15 \sin (1000 \pi t)$ is modulated by $10 \sin (4 \pi t)$ signal. The amplitude modulated signal contains frequency(ies) of$A) 500 \text{ Hz}$$B) 2 \text{ Hz}$$C) 250 \text{ Hz}$$D) 498 \text{ Hz}$$E) 502 \text{ Hz}$Choose the correct answer from the options given below: