The amine that reacts with Hinsberg's reagent | vedclass

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Question

(A) Hinsberg's reagent (benzene sulfonyl chloride,$C_6H_5SO_2Cl$) is used to distinguish between primary,secondary,and tertiary amines.$1$. Primary $(

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$(CH_3)_2CH-NH-CH(CH_3)_2$

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(A) Hinsberg's reagent (benzene sulfonyl chloride,$C_6H_5SO_2Cl$) is used to distinguish between primary,secondary,and tertiary amines.$1$. Primary $(1^\circ)$ amines react to form $N$-alkylbenzene sulfonamides,which contain an acidic hydrogen on the nitrogen atom and are therefore soluble in alkali.$2$. Secondary $(2^\circ)$ amines react to form $N,N$-dialkylbenzene sulfonamides,which lack an acidic hydrogen on the nitrogen atom and are insoluble in alkali.$3$. Tertiary $(3^\circ)$ amines do not react with Hinsberg's reagent.In the given options,$(CH_3)_2CH-NH-CH(CH_3)_2$ is a secondary amine. It reacts with Hinsberg's reagent to form an $N,N$-disubstituted sulfonamide that has no acidic hydrogen,making it insoluble in alkali.

The amine that reacts with Hinsberg's reagent to give an alkali-insoluble product is:

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