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Question

(C) The adiabatic elasticity of a gas is given by the formula $E_{adiabatic} = \gamma P$,where $\gamma$ is the adiabatic index and $P$ is the pressure

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$1.4 	imes 10^5$

Vedclass · Answer

(C) The adiabatic elasticity of a gas is given by the formula $E_{adiabatic} = \gamma P$,where $\gamma$ is the adiabatic index and $P$ is the pressure.For a diatomic gas,the adiabatic index $\gamma = \frac{C_p}{C_v} = \frac{7/2 R}{5/2 R} = 1.4$.At $NTP$ (Normal Temperature and Pressure),the pressure $P$ is approximately $1.013 	imes 10^5 \, N/m^2$.Substituting these values,we get $E_{adiabatic} = 1.4 	imes 1.013 	imes 10^5 \, N/m^2$.$E_{adiabatic} \approx 1.418 	imes 10^5 \, N/m^2$.Rounding to the nearest provided option,the value is $1.4 	imes 10^5 \, N/m^2$.

The adiabatic elasticity of a diatomic gas at $NTP$ is ........ $N/m^2$.

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