The addition of dilute $NaOH$ to $Cr^{3+}$ salt solution will give:

  • A
    a solution of $[Cr(OH)_{4}]^{-}$
  • B
    precipitate of $Cr_{2}O_{3} \cdot nH_{2}O$
  • C
    precipitate of $[Cr(OH)_{6}]^{3-}$
  • D
    precipitate of $Cr(OH)_{3}$

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