The actinoids exhibit a greater number of oxidation states in general than the lanthanoids. This is because

  • A
    the $5f$ orbitals extend further from the nucleus than the $4f$ orbitals
  • B
    the $5f$ orbitals are more buried than the $4f$ orbitals
  • C
    there is a similarity between $4f$ and $5f$ orbitals in their angular part of the wave function
  • D
    the actinoids are more reactive than the lanthanoids

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