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(A) Energy is released $(\varepsilon > 0)$ in a nuclear reaction if the total binding energy of the products is greater than the total binding energy

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$(i)$ and $(iv)$

Vedclass · Answer

(A) Energy is released $(\varepsilon > 0)$ in a nuclear reaction if the total binding energy of the products is greater than the total binding energy of the reactants.For reaction $(i)$: $A + B 	o C$. Since $C$ has a higher binding energy per nucleon than $A$ and $B$,the total binding energy increases,so $\varepsilon > 0$ (Nuclear Fusion).For reaction $(iv)$: $F 	o D + E$. Since $D$ and $E$ have higher binding energy per nucleon than $F$,the total binding energy increases,so $\varepsilon > 0$ (Nuclear Fission).Thus,$\varepsilon$ is positive for reactions $(i)$ and $(iv)$.

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