The T.V. transmission tower in Delhi has a he | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The formula for the maximum line-of-sight distance $d$ for a transmission tower of height $h$ is given by $d = \sqrt{2hR}$,where $R$ is the radius

Vedclass · Accepted Answer

$56$

Vedclass · Answer

(C) The formula for the maximum line-of-sight distance $d$ for a transmission tower of height $h$ is given by $d = \sqrt{2hR}$,where $R$ is the radius of the Earth.Given: $h = 245 \ m$,$R = 6.4 	imes 10^6 \ m$.Substituting the values:$d = \sqrt{2 	imes 245 	imes 6.4 	imes 10^6}$$d = \sqrt{490 	imes 6.4 	imes 10^6}$$d = \sqrt{3136 	imes 10^6}$$d = 56 	imes 10^3 \ m$$d = 56 \ km$.Thus,the broadcast can be received up to a distance of $56 \ km$.

The $T.V.$ transmission tower in Delhi has a height of $245 \ m$. The distance up to which the broadcast can be received (taking the radius of earth to be $6.4 \times 10^6 \ m$) is........$km$ :

Similar Questions

The nature of electromagnetic waves is

If $z=\log (\tan x+\tan y)$,then $(\sin 2x) \frac{\partial z}{\partial x}+(\sin 2y) \frac{\partial z}{\partial y}$ is equal to

What should be the angular speed of the earth,so that a body lying on the equator may appear weightless? $(g = 10\,m/s^2, R = 6400\,km)$

$A$ constant torque acting on a uniform circular wheel changes its angular momentum from $A_0$ to $4A_0$ in $4 \ s$. The magnitude of this torque is

Let $Z$ denote the set of integers. Define $f: Z \rightarrow Z$ by $f(x) = \begin{cases} \frac{x}{2}, & x \text{ is even} \\ 0, & x \text{ is odd} \end{cases}$. Then $f$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module