The I-V characteristics of a metal wire at tw | vedclass

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Question

(B) For a metal wire,the resistance $R$ increases with an increase in temperature.The slope of the $I-V$ graph is given by $\frac{I}{V} = \frac{1}{R}$

Vedclass · Accepted Answer

$T_{1} < T_{2}$

Vedclass · Answer

(B) For a metal wire,the resistance $R$ increases with an increase in temperature.The slope of the $I-V$ graph is given by $\frac{I}{V} = \frac{1}{R}$.From the figure,the slope of the line corresponding to $T_{1}$ is greater than the slope of the line corresponding to $T_{2}$.Therefore,$\frac{1}{R_{1}} > \frac{1}{R_{2}}$,which implies $R_{1} Since resistance increases with temperature,$R_{1} < R_{2}$ implies $T_{1} < T_{2}$.

The $I-V$ characteristics of a metal wire at two different temperatures ($T_{1}$ and $T_{2}$) are given in the adjoining figure. Here,we can conclude that:

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