The Q-value of a series LCR circuit with L=2 | vedclass

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Question

(A) The $Q$-factor (quality factor) of a series $LCR$ circuit is given by the formula:$Q = \frac{1}{R} \sqrt{\frac{L}{C}}$Given values are:$L = 2 \ H$

Vedclass · Accepted Answer

$12.5$

Vedclass · Answer

(A) The $Q$-factor (quality factor) of a series $LCR$ circuit is given by the formula:$Q = \frac{1}{R} \sqrt{\frac{L}{C}}$Given values are:$L = 2 \ H$$C = 32 \ \mu F = 32 	imes 10^{-6} \ F$$R = 20 \ \Omega$Substituting these values into the formula:$Q = \frac{1}{20} \sqrt{\frac{2}{32 	imes 10^{-6}}}$$Q = \frac{1}{20} \sqrt{\frac{1}{16 	imes 10^{-6}}}$$Q = \frac{1}{20} 	imes \frac{1}{4 	imes 10^{-3}}$$Q = \frac{1}{20} 	imes \frac{1000}{4}$$Q = \frac{250}{20} = 12.5$Thus,the $Q$-value is $12.5$.

The $Q$-value of a series $LCR$ circuit with $L=2 \ H$,$C=32 \ \mu F$,and $R=20 \ \Omega$ is:

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