The pH of 10^{-8} M HCl solution is | vedclass

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(D) $HCl$ is a strong acid. All acids have a $pH$ in the acidic range,i.e.,below $7$. The concentration of $HCl$ is given as $10^{-8} \ M$. $pH$ is ca

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Between $6-7$

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(D) $HCl$ is a strong acid. All acids have a $pH$ in the acidic range,i.e.,below $7$. The concentration of $HCl$ is given as $10^{-8} \ M$. $pH$ is calculated by considering the contribution of protons from both the acid and the water. Since $10^{-8} \ M$ is a very low concentration,the contribution of $H^+$ ions from the auto-ionization of water $(10^{-7} \ M)$ cannot be ignored. Total $[H^+] = [H^+]_{acid} + [H^+]_{water} = 10^{-8} + 10^{-7} = 1.1 	imes 10^{-7} \ M$. $pH = -\log[H^+] = -\log(1.1 	imes 10^{-7}) = 7 - \log(1.1) \approx 6.96$. This value lies between $6$ and $7$. Thus,the correct answer is option $(d)$.

The $pH$ of $10^{-8} \ M \ HCl$ solution is

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