The d-electronic configuration of an octahedr | vedclass

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(C) The magnetic moment $\mu$ is given by the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.Given $\mu = 3.95 \ BM$

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$t_{2g}^5 e_g^2$

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(C) The magnetic moment $\mu$ is given by the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.Given $\mu = 3.95 \ BM$,we have $\sqrt{n(n+2)} \approx 3.95$,which implies $n(n+2) \approx 15.6$,so $n \approx 3$.$Co(II)$ has a $3d^7$ configuration.In an octahedral field,the $d$-orbitals split into $t_{2g}$ and $e_g$ sets.For a $d^7$ system with $3$ unpaired electrons,the configuration is $t_{2g}^5 e_g^2$ (high spin).This corresponds to $5$ electrons in $t_{2g}$ (with $1$ unpaired) and $2$ electrons in $e_g$ (with $2$ unpaired),totaling $3$ unpaired electrons.

The $d$-electronic configuration of an octahedral $Co(II)$ complex having magnetic moment of $3.95 \ BM$ is :

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