The 15^{th} term of the A.P. 1, 11, 21, 31, d | vedclass

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Question

(C) The given $A.P.$ is $1, 11, 21, 31, \dots$Here,the first term $a = 1$.The common difference $d = 11 - 1 = 10$.The formula for the $n^{th}$ term of

Vedclass · Accepted Answer

$141$

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(C) The given $A.P.$ is $1, 11, 21, 31, \dots$Here,the first term $a = 1$.The common difference $d = 11 - 1 = 10$.The formula for the $n^{th}$ term of an $A.P.$ is $T_n = a + (n - 1)d$.To find the $15^{th}$ term,we substitute $n = 15$,$a = 1$,and $d = 10$ into the formula:$T_{15} = 1 + (15 - 1) 	imes 10$$T_{15} = 1 + 14 	imes 10$$T_{15} = 1 + 140$$T_{15} = 141$Therefore,the $15^{th}$ term is $141$.

The $15^{th}$ term of the $A.P.$ $1, 11, 21, 31, \dots$ is........

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