The n^{th} term of an A.P. is given by T_{n} | vedclass

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(B) The $n^{th}$ term of the $A.P.$ is given by $T_{n} = 3n - 1$.To find the common difference $d$,we calculate the first two terms of the sequence.Fo

Vedclass · Accepted Answer

$3$

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(B) The $n^{th}$ term of the $A.P.$ is given by $T_{n} = 3n - 1$.To find the common difference $d$,we calculate the first two terms of the sequence.For $n = 1$,$T_{1} = 3(1) - 1 = 3 - 1 = 2$.For $n = 2$,$T_{2} = 3(2) - 1 = 6 - 1 = 5$.The common difference $d$ is defined as $d = T_{2} - T_{1}$.Substituting the values,$d = 5 - 2 = 3$.Thus,the common difference of the $A.P.$ is $3$.

The $n^{th}$ term of an $A.P.$ is given by $T_{n} = 3n - 1$. Then,the common difference of the $A.P.$ is ...........

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