The $pH$ of a sample of vinegar is $3.76$. Calculate the concentration of hydrogen ion in it.
(N/A) Given,$pH = 3.76$.
It is known that,
$pH = -\log [H^{+}]$
$\Rightarrow \log [H^{+}] = -pH$
$\Rightarrow [H^{+}] = \text{antilog}(-pH)$
$= \text{antilog}(-3.76)$
$= 1.74 \times 10^{-4} \ M$.
Hence,the concentration of hydrogen ion in the given sample of vinegar is $1.74 \times 10^{-4} \ M$.
It is known that,
$pH = -\log [H^{+}]$
$\Rightarrow \log [H^{+}] = -pH$
$\Rightarrow [H^{+}] = \text{antilog}(-pH)$
$= \text{antilog}(-3.76)$
$= 1.74 \times 10^{-4} \ M$.
Hence,the concentration of hydrogen ion in the given sample of vinegar is $1.74 \times 10^{-4} \ M$.
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